What a beastie... What's going on with the swinging arm ?

A parallelogram swinging arm avoids the reaction of load changes which are produced by a shaft drive, which was used by MV in the early years...wonder if my technical explanations are understandable ?

Yeah, what Renn said.....plus this will make it absolutely clear:

Parallelogram

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A parallelogram. Opposite sides are parallel and congruent. The parallelogram in this case is a Rhomboid as its angles are oblique

In geometry, a parallelogram is a quadrilateral with two sets of parallel sides. The opposite or facing sides of a parallelogram are of equal length, and the opposite angles of a parallelogram are equal. The three-dimensional counterpart of a parallelogram is a parallelepiped.
Contents
[hide]

* 1 Properties
* 2 Types of parallelograms
* 3 Proof that diagonals bisect each other
* 4 The area formula
* 5 Computing the area of a parallelogram
* 6 See also
* 7 External links

[edit] Properties

* Opposite sides of a parallelogram are equal in length.
* Opposite angles of a parallelogram are equal in measure.
* The area, A, of a parallelogram is A = bh, where b is the base of the parallelogram and h is its height.
* Opposite sides of a parallelogram will never intersect.
* The area of a parallelogram is twice the area of a triangle created by one of its diagonals.
* The area of a parallelogram is also equal to the magnitude of the vector cross product of two adjacent sides.
* The diagonals of a parallelogram bisect each other.
* Any non-degenerate affine transformation takes a parallelogram to another parallelogram.
There is an infinite number of affine transformations which take any given parallelogram to a square.

[edit] Types of parallelograms

* Rhomboid - A quadrilateral whose opposite sides are parallel and unequal, and whose angles are not right angles
* Rectangle - A parallelogram with four angles of equal size (right angles).
* Rhombus - A parallelogram with four sides of equal length.
* Square - A parallelogram with four sides of equal length and four angles of equal size (right angles).

[edit] Proof that diagonals bisect each other
Parallelogram ABCD

To prove that the diagonals of a parallelogram bisect each other, first note a few pairs of equivalent angles:

\angle ABE \cong \angle CDE (alternate)
\angle BAE \cong \angle DCE (alternate).

Since they are angles that a transversal makes with parallel lines AB and DC.

Also, \angle AEB \cong \angle CED since they are a pair of vertical angles.

Therefore, \triangle ABE \sim \triangle CDE since they have the same angles.

From this similarity, one has the ratios

{AB \over CD} = {AE \over CE} = {BE \over DE}.

Since AB = DC, we have

{AB \over CD} = 1.

Therefore,

AE = CE
BE = DE.

E bisects the diagonals AC and BD.

It can also be proved that the diagonals bisect each other, by placing the parallelogram on a coordinate grid, and assigning variables to the vertices, it can be shown that the diagonals have the same midpoint.

There is yet another way to prove that the diagonals of a parallelogram bisect each other.

It is known that AB = DC, because opposite sides of a parallelogram are equal in length. We also know that segment AB is parallel to segment DC by the definition of a parallelogram. If two parallel lines are cut by a transversal, alternate interior angles are equal in measure. Therefore, angle BAE is equal to angle DCE, and angle ABE is equal to angle CDE. The ASA postulate proves triangles ABE and CDE congruent. Corresponding sides of congruent triangles are equal in length, so AE = CE and BE = DE. Thus E is the mid-point of AC, and also of BD, so these diagonals of the parallelogram bisect each other.

[edit] The area formula
Area of the parallelogram is in blue

The area formula,

A = B \times H,\,

can be derived as follows:

The area of the parallelogram to the right (the blue area) is the total area of the rectangle less the area of the two orange triangles. The area of the rectangle is

A_\text{rect} = (B+A) \times H\,

and the area of a single orange triangle is

A_\text{tri} = \frac{1}{2} A \times H\, or S_\text{tri} = \frac{1}{2} bh.

Therefore, the area of the parallelogram is

A = A_\text{rect} - 2 \times A_\text{tri} = \left( (B+A) \times H \right) - \left( A \times H \right) = B \times H.\,

[edit] Computing the area of a parallelogram

Let a,b\in\R^2 and let V=[a\ b]\in\R^{2\times2} denote the matrix with columns a and b. Then the area of the parallelogram generated by a and b is equal to | det(V) |

Let a,b\in\R^n and let V=[a\ b]\in\R^{n\times2} Then the area of the parallelogram generated by a and b is equal to \sqrt{\det(V^T V)}

Let a,b,c\in\R^2. Then the area of the parallelogram is equivalent to the absolute value of the determinant of a matrix built using a, b and c as rows with the last column padded using ones as follows:

V = \left| \det \begin{bmatrix} a_1 & a_2 & 1 \\ b_1 & b_2 & 1 \\ c_1 & c_2 & 1 \end{bmatrix} \right|.

[edit] See also

* Fundamental parallelogram

[edit] External links
Search
Parallelogram

* Parallelogram and Rhombus - Animated course (Construction, Circumference, Area)
* Weisstein, Eric W., "Parallelogram" from MathWorld.
* Interactive Parallelogram --sides, angles and slope
* Area of Parallelogram at cut-the-knot
* Equilateral Triangles On Sides of a Parallelogram at cut-the-knot
* Definition and properties of a parallelogram with animated applet
* Interactive applet showing parallelogram area calculation interactive applet


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that's exactly what I was going to say

a bit more trivial

http://books.google.de/books?id=84hF-qoR5I...arm&f=false

[quote name='Russell Burrows' date='Aug 14 2009, 18:38' post='3796161']
Yeah, what Renn said.....plus this will make it absolutely clear:

Glad we've cleared that one up Russell.Its been keeping me awake many a night!
HW

Sorry about that gents...wasn't taking the Mick, Renn....

I suspect this version is later?

Pity it doesn't show the right side, but I assume we would see a chain drive

Am I mistaken but I have seen several shots of the MV at this time with siameezed pipes, 2-4, with a pair of megga's.
Do you have any idea where Ray Fay came from, one of the 'Brains Trust' must know please.
Roy

99% sure that Ray Fay was a Scouser.

Not only that, he was the first European to ride a factory Suzuki.

Thanks for that LarryD, I saw him on the Suzuki Coleda when he was the the team manager at the TT. Something in my mind said American.
Ray had been on the W/C trail for several years before this appointment.
First non-Japanese on a Honda was Bill Hunt, American team manager of Honda 1959. Was not Sony Angel the first non Japanese to race a Yamaha in Europe?
That Murray Walker sound-alike. Jack (Carbuncle) Burnicle said last week Tommy Robb was the first British works rider on a Honda. He speaks a lot of waffle but I think he was correct.
Roy

Roger that, Ray Fay was a Liverpudlian who was drafted into Suzuki's 1960 TT squad to replace Mitsuo Itoh, who had crashed and injured his knee. He got the ride by virtue of being a Shell-contracted rider, appointed by Lew Ellis.

Source : Team Suzuki by Ray Battersby

I thought Jim Redman was British.Might have lived in Rodesia but came from London

Yes, Jim was English. But Tommy Robb wasn't approached by Honda until late 1961, by which time Hailwood and McIntyre were already on the books. More research needed, Jack....

His nickname must have been King Kong ?

Hi Boys I thought this about Tommy Robb would stir things up. Yes I conceed Jim Redman was born in the UK but all his entries were always Southern Rhodesia. Like wise Gary Hocking, born in Wales always entered his country as Southern Rhodesia.
Yes in 1962 the first English rider to win a W/C race on a Honda was Derek Minter, but this was not a Honda works entry. He was contracted by Hondis, the UK Honda distributors.
Likewise Mike Hailwoods Hondas for 1961 were obtained by his father Stan from Honda, with the threat that Kings of Oxford would not sell any Hondas if the deal fell through.
If you study Bob McIntyres Honda in the 1961 250 TT it had the Potts modified twin airintakes either side of the front number plate, with flexible tubes to the Carb area. Just the same as Bob and Aliistair Kings 350 Bianchi. I may be on sticky ground here but I think again in 1961 Bobs Honda was not a direct works entry.
All these non works entries back fired on Honda and it did not happen again.
Roy

Jim was from Greenford, Middlesex, near Harrow. I think he left for Rhodesia when around eighteen and was there for only about six years before returning here to race. Garry was taken there as a nipper and stayed when the family returned to Wales. Both though defined themselves as Rhodesian, so I suppose that's what matters.

John Hartle also rode a 250 four in '61 and I think he wasn't alowed to race it outside of the UK. Then there was an oil company contract issue that prevented him getting a full Honda contract?

You are right Russell, I had forgot John, he was such a stylish rider and quite approachable. It was such a loss to the sport when he died at Scarborough. He certainly gave John Surtees a run for his money on the MV-4 and MV-6.
Thanks for the info.
Roy

The Les Graham bike appears to have only two meggas, Roy. I'll have to try and find some more pics.

Haven't discovered any further photos, but did find this eye witness account of Les's last race.
http://www.bbhmg.com/tt53a.htm

Dennis Quinlan has posted some more of Keith Bryen's fascinating photographs from the 50's at http://velobanjogent.blogspot.com/ These are as equally wonderful as the stuff we've seen so far. And just in case you drop by : thanks so much Keith and Dennis.

Is anybody going to have a go at this ??? WWW

Thanks for that Russell, those photos of Keith Bryen are fantastic. 1956 and in colour, this was still in the b/w era.
Well done Keith for letting us into your European racing world. Sad he lost his Guzzi ride so soon.
Roy

Hi Phil
Is that an AJS or Matchless twin?
I can't offer a guess on the rider (although the number 1 plate suggests a notable).

[quote name='fil2.8' date='Aug 15 2009, 18:48' post='3796992']
Is anybody going to have a go at this ??? WWW







It does look AMCish around '63 ? You gonna give us clue on the pilot?

Watcha Barry Was there a difference apart from the badge ??? Listed as a AJS

It does look AMCish around '63 ? You gonna give us clue on the pilot?
[/quote]

Russ , if you look at ' Motor Cycle ' 23rd April 1964 you will find the answer !!!! oh yes page 500 , top left

Yes Roy, Keith explained recently that he was expecting to go back to Europe in '58 but received a letter from Guzzi telling him they were pulling out, so his career then stopped. He said he never went near a racing bike until the late seventies when he did some vintage racing/parading.

Ah shucks, the one copy I don't have.... Wild punt, Canadian Dave Wildman.

Do you want a butchers at my copy then ?? No Russ , it's a Brit , probably one of the best known proddie riders of his era , indeed winning this race !!! in '64

My wild punt - Brian Setchell?

He won in '64 but on a Norton......

See what you mean about ' wild ' Barry . No , sorry , it's not Luton's Brian Setchell

So not the thruxton 500 miler ?

No , a national meeting at Brands , he was better known racing ' Bonnies ' for a large concern

Has he buggerd off to the boozer...? Erm, final go, clutching at straws...Peter Butler?

Feeling more confident now.

Who ?? Me , no staying in watching Speedway GP + 20 /20 Cricket final -- Somerset / Sussex

Yep Russ , you got there in the end well done !!! good straw clutching !!!

Yep -nice one Russ

ok , then chaps , try this , page 517 , same issue

Chris Vincent?

Barry , you little tinker have you got that issue , if not , very well done i'll find another pic..........................

Right , smart arse WWW

Tom Phillips maybe?

You must have that copy of ' Motor Cycle ' Barry well done it is Tom

Honest Phil - I don't have a copy of the mag!
I have only seen Tom pictured on an Avon-faired Manx (Minter-type), so was not 100% sure it was him. I recognised his helmet (and the facemask). I remember one of the first meetings I spectated at as a boy, Llandow in the mid-sixties, when Tom was Vic Camp's runner on the Ducatis.

last one tonight .............. have a go

Schiedigger 47 chasing Vincent, hairpin, Mallory ?

Or not....perhaps the Birch brothers on the first be'em ?

Didn't think Fritz was as old as 47 Russ . But you are correct
Hang on , a cotton picking minute , how about the other outfit ?? who's the pilot ??

Wrong on your edit

Mmmm.... but perhaps correct the first time ?

Could it be Florian Camathis?? Possibly on the Gilera???

Russ , although you are correct with Fritz and Chris , the hidden plot is.....................................who ??